(x^2+3xy-7)-(x^2-2xy+4)=

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Solution for (x^2+3xy-7)-(x^2-2xy+4)= equation:


Simplifying
(x2 + 3xy + -7) + -1(x2 + -2xy + 4) = 0

Reorder the terms:
(-7 + 3xy + x2) + -1(x2 + -2xy + 4) = 0

Remove parenthesis around (-7 + 3xy + x2)
-7 + 3xy + x2 + -1(x2 + -2xy + 4) = 0

Reorder the terms:
-7 + 3xy + x2 + -1(4 + -2xy + x2) = 0
-7 + 3xy + x2 + (4 * -1 + -2xy * -1 + x2 * -1) = 0
-7 + 3xy + x2 + (-4 + 2xy + -1x2) = 0

Reorder the terms:
-7 + -4 + 3xy + 2xy + x2 + -1x2 = 0

Combine like terms: -7 + -4 = -11
-11 + 3xy + 2xy + x2 + -1x2 = 0

Combine like terms: 3xy + 2xy = 5xy
-11 + 5xy + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
-11 + 5xy + 0 = 0
-11 + 5xy = 0

Solving
-11 + 5xy = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 5xy = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 5xy = 0 + 11
5xy = 0 + 11

Combine like terms: 0 + 11 = 11
5xy = 11

Divide each side by '5y'.
x = 2.2y-1

Simplifying
x = 2.2y-1

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